-24x^2-72x+240=0

Solution for -24x^2-72x+240=0 equation:

-24x^2-72x+240=0

a = -24; b = -72; c = +240;
Δ = b2-4ac
Δ = -722-4·(-24)·240
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-168}{2*-24}=\frac{-96}{-48}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+168}{2*-24}=\frac{240}{-48}
=-5
$